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5578146)
Since findPool() is sorted, a binary search is more appropriate than
a linear search.
* Return null if not in a Pool.
* Assume pools is sorted.
*/
* Return null if not in a Pool.
* Assume pools is sorted.
*/
- if (p >= gc.min_addr && p < gc.max_addr)
- {
- if (gc.pools.length == 1)
- {
- return gc.pools[0];
- }
-
- for (size_t i = 0; i < gc.pools.length; i++)
- {
- Pool* pool = gc.pools[i];
- if (p < pool.topAddr)
- {
- if (pool.baseAddr <= p)
- return pool;
- break;
- }
- }
+ if (p < gc.min_addr || p >= gc.max_addr)
+ return null;
+ if (gc.pools.length == 0)
+ return null;
+ if (gc.pools.length == 1)
+ return gc.pools[0];
+ /// The pooltable[] is sorted by address, so do a binary search
+ size_t low = 0;
+ size_t high = gc.pools.length - 1;
+ while (low <= high) {
+ size_t mid = (low + high) / 2;
+ auto pool = gc.pools[mid];
+ if (p < pool.baseAddr)
+ high = mid - 1;
+ else if (p >= pool.topAddr)
+ low = mid + 1;
+ else
+ return pool;